5=1/5(x-4)^2

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Solution for 5=1/5(x-4)^2 equation: 



5=1/5(x-4)^2

We move all terms to the left:

5-(1/5(x-4)^2)=0



Domain of the equation: 5(x-4)^2)!=0

x∈R



We multiply all the terms by the denominator


-(1+5*5(x-4)^2)=0



We calculate terms in parentheses: -(1+5*5(x-4)^2), so:

1+5*5(x-4)^2

determiningTheFunctionDomain
5*5(x-4)^2+1

Wy multiply elements

25x(x+1

Back to the equation:

-(25x(x+1)





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